A solution of sulfuric acid (H₂SO₄, 25.00 mL) was titrated to completion with 34.55 mL of 0.1020 M sodium hydroxide. What was the concentration of the sulfuric acid?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction between sulfuric acid (H₂SO₄) and sodium hydroxide (NaOH) is: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O. This indicates that 1 mole of sulfuric acid reacts with 2 moles of sodium hydroxide. Given that 34.55 mL of 0.1020 M NaOH is used, the moles of NaOH are (34.55 mL) * (0.1020 mol/L) = 0.035241 mol. Since the stoichiometry of the reaction is 1:2, the moles of H₂SO₄ are half of the moles of NaOH, which is 0.035241 mol / 2 = 0.0176205 mol. The concentration of sulfuric acid is then the moles of H₂SO₄ divided by the volume of the solution in liters, which is 0.0176205 mol / 0.025 L = 0.70482 M, or 0.07048 M when rounded to the correct number of significant figures.

A Solution of Sulfuric Acid (H2SO4, 25

A Solution of Sulfuric Acid (H₂SO₄, 25