In the combustion of methane, CH₄(g) + 2 O₂(g) $\rightarrow$CO₂(g) + 2 H₂O (g), which reactant has the greatest rate of disappearance?

Question

Quizplus · Accepted Answer

The balanced equation indicates that 2 moles of O₂ are needed to react with 1 mole of CH₄. Therefore, O₂ is the limiting reactant and will be consumed first. This means that O₂ has the greatest rate of disappearance.

In the Combustion of Methane, CH4(g) + 2 O2(g) →\rightarrow→ CO2(g) + 2 H2O (G), Which Reactant Has the Greatest

In the Combustion of Methane, CH₄(g) + 2 O₂(g) $\rightarrow$ CO₂(g) + 2 H₂O (G), Which Reactant Has the Greatest