If the rate of appearance of O₂ in the reaction:
2O₃(g) $\rightarrow$ 3O₂(g)
Is 0.250 M/s over the first 5.50 s, how much oxygen will form during this time?

Name: If the rate of appearance of O 2 in the reaction: 2O 3 (g) $\rightarrow$3O 2 (g) Is 0.250 M/s over the first 5.50 s, how much oxygen will form during this time?
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Question

If the rate of appearance of O₂ in the reaction: 2O₃(g) $\rightarrow$3O₂(g) Is 0.250 M/s over the first 5.50 s, how much oxygen will form during this time?

Quizplus · Accepted Answer

The rate of appearance of O₂ is 0.250 M/s. Over 5.50 seconds, the amount of O₂ formed is 0.250 M/s * 5.50 s = 1.375 M, which rounds to 1.38 M.

If the Rate of Appearance of O2 in the Reaction →\rightarrow→

If the Rate of Appearance of O₂ in the Reaction $\rightarrow$