Based on the following graph, which metal will emit the highest energy photoelectron when a photon with a frequency of 3.9 * 10¹⁴ Hz is incident on the metal?

Question

Quizplus · Accepted Answer

The energy of a photoelectron is given by the equation E = hf - BE, where E is the energy of the photoelectron, hf is the energy of the incident photon, and BE is the binding energy of the electron to the metal. To find the metal that will emit the highest energy photoelectron, we need to find the metal with the smallest BE. From the graph, we can see that metal A has the smallest BE, so it will emit the highest energy photoelectron when a photon with a frequency of 3.9 x 10^14 Hz is incident on it.

Based on the Following Graph, Which Metal Will Emit the Highest