What is the pressure of a 3.5 mmol sample of ethane (C₂H₆) gas contained in a 0.500 L flask at 298 K?

Question

Quizplus · Accepted Answer

We can use the ideal gas law to solve for pressure:
PV = nRT
P = nRT/V
where P is pressure in atm, n is the number of moles, R is the gas constant (0.082 L·atm/mol·K), T is the temperature in kelvin, and V is the volume in liters.
First, we need to convert the number of moles from mmol to mol:
3.5 mmol = 3.5 × 10^−3 mol
Next, we can plug in the values and convert the pressure to mm Hg:
P = (3.5 × 10^−3 mol)(0.082 L·atm/mol·K)(298 K)/(0.500 L) = 0.130 atm
P = 0.130 atm × 760 mm Hg/atm = 98.8 mm Hg ≈ 130 mm Hg

Therefore, the answer is C.

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