If P(A) = 0.35, P(B) = 0.60, and P(A or B) = 0.70, then:
A)A and B are mutually exclusive.
B)P(A∩B) = .15.
C)P(A∩B) = .25.
D)P(A∩B) = .35.

Name: If P(A) = 0.35, P(B) = 0.60, and P(A or B) = 0.70, then: A)A and B are mutually exclusive. B)P(A∩B) = .15. C)P(A∩B) = .25. D)P(A∩B) = .35.
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Question

Quizplus · Accepted Answer

Since P(A or B) = P(A) + P(B) - P(A∩B), we can plug in the given values to get:
0.70 = 0.35 + 0.60 - P(A∩B)
0.15 = P(A∩B)
Therefore, the answer is (C) P(A∩B) = 0.25.