If the sample proportions are p₁ = 15/60 and p₂ = 20/90, normality may be assumed in a test comparing the two population proportions.

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Quizplus · Accepted Answer

In order for normality to be assumed in a test comparing two population proportions, the sample size should be large enough. A commonly used rule of thumb is that both np and n(1-p) should be greater than 10, where n is the sample size and p is the sample proportion. For the first sample proportion, np₁ = 60 * (15/60) = 15 and n(1-p)₁ = 60 * (1-15/60) = 45/2, which are both greater than 10. Similarly, for the second sample proportion, np₂ = 90 * (20/90) = 20 and n(1-p)₂ = 90 * (1-20/90) = 70/3, which are both greater than 10. Therefore, we can assume normality in a test comparing the two population proportions.

If the Sample Proportions Are P1 = 15/60 and P2

If the Sample Proportions Are P₁ = 15/60 and P₂