A nuclide has a decay constant of 4.28 × 10^-4/h. If the activity of a sample is 3.14 × 10⁵/s, how many atoms of the nuclide are present in the sample?

Question

Quizplus · Accepted Answer

We can use the equation N = A/λ, where N is the number of atoms present, A is the activity, and λ is the decay constant.

Plugging in the values, we get:

N = (3.14 × 10^15)/4.28 × 10^-14

N = 2.64 × 10^29

Therefore, the number of atoms present in the sample is 2.64 × 10^29.

The only option that matches this value is option B.

A Nuclide Has a Decay Constant of 4