Determine E°cell for the reaction: 2 Al + 3 Zn²⁺ → 2 Al³⁺ + 3 Zn. The half reactions are: Al³⁺(aq) + 3 e- → Al(s) E° = -1.676 V
Zn²⁺(aq) + 2 e- → Zn(s) E° = -0.763 V

Question

Determine E°cell for the reaction: 2 Al + 3 Zn²⁺ → 2 Al³⁺ + 3 Zn. The half reactions are: Al³⁺(aq) + 3 e- → Al(s) E° = -1.676 V Zn²⁺(aq) + 2 e- → Zn(s) E° = -0.763 V

Quizplus · Accepted Answer

The correct answer is A because the E°cell is calculated by subtracting the E° of the anode from the E° of the cathode. In this case, the anode is the Al³⁺/Al half-reaction and the cathode is the Zn²⁺/Zn half-reaction. Therefore, E°cell = E°cathode - E°anode = (-0.763 V) - (-1.676 V) = 0.913 V.

Determine E°cell for the Reaction: 2 Al + 3 Zn2+

Determine E°cell for the Reaction: 2 Al + 3 Zn²⁺