Determine E°cell for the reaction: Pb + Cu2+ → Pb2+ + Cu. The half reactions are: Pb2+(aq) + 2 e- → Pb(s) E° = -0.125 V
Cu2+ + 2 e- → Cu E° = 0.340 V
A) 0.215 V
B) 0.465 V
C) 0.930 V
D) -0.215 V
E) -0.465 V
Correct Answer:
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