Consider the following reaction: 2 Al + 3 Ni2+ → 2 Al3+ + 3 Ni E° = 1.410 v
What would be the cell potential at 25°C as calculated from the Nernst equation if [Ni2+] = 0.020 M, [Al3+] = 3.60 M?

Question

Quizplus · Accepted Answer

The Nernst equation is given by: 
Ecell = E° - (RT/nF) * ln(Q)
where E° = 1.410 V, R = 8.314 J/mol-K, T = 298 K, n = 6 (from the balanced equation), F = 96,485 C/mol.
Q = [Al3+]^2/[Ni2+]^3 = (3.60 M)^2/(0.020 M)^3 = 324,000 M^-1
Plugging in the values, 
Ecell = 1.410 - (8.314*298/6*96485) * ln(324000) 
Ecell = 1.349 V 
Therefore, the answer is D, 1.349 volts.

Consider the Following Reaction: 2 Al + 3 Ni2+ →