Consider the reaction: H₂X(g) → HX(g) + X(g)
ΔH°rxn = 18.4 kJ/mol ΔS°rxn = 23.1 J/mol-K
What is Keq for this reaction at 525 K?

Name: Consider the reaction: H 2 X(g) → HX(g) + X(g) ΔH°rxn = 18.4 kJ/mol ΔS°rxn = 23.1 J/mol-K What is Keq for this reaction at 525 K?
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Question

Consider the reaction: H₂X(g) → HX(g) + X(g) ΔH°rxn = 18.4 kJ/mol ΔS°rxn = 23.1 J/mol-K What is Keq for this reaction at 525 K?

Quizplus · Accepted Answer

To find Keq, use the equation ΔG° = ΔH° - TΔS°. Convert ΔS° to kJ/mol-K, then calculate ΔG° at 525 K. Use ΔG° = -RTln(Keq) to solve for Keq.

Consider the Reaction: H2X(g) → HX(g) + X(g)

Consider the Reaction: H₂X(g) → HX(g) + X(g)