The solubility product constant of silver sulfate is 1.6 × 10-5. What is the molar solubility of this compound?

Question

Quizplus · Accepted Answer

We can write the solubility product expression as:
Ag2SO4(s) ⇌ 2Ag+(aq) + SO42-(aq)
Ksp = [Ag+]^2[SO42-]
Let x be the molar solubility of Ag2SO4. Then:
Ksp = x^2(2x) = 4x^3
1.6 × 10^-5 = 4x^3
x = (1.6 × 10^-5 / 4)^(1/3) = (4/16)^(1/3) × 10^-1 = (1/2)^(1/3) × 10^-1
x = (16/4)^(1/3) × 10^-1 = (4)^(1/3) × 10^-1
x = (1/2)^(2/3) × 10^-1
x = (16/4)^(2/3) × 10^-1
Among the given choices, only option C matches this value. Therefore, the answer is C.

The Solubility Product Constant of Silver Sulfate Is 1