The solubility of a salt MX2 with a molar mass of 170 g/mol is 12.7 g/liter. Calculate the Ksp.

Name: The solubility of a salt MX2 with a molar mass of 170 g/mol is 12.7 g/liter. Calculate the Ksp.
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Quizplus · Accepted Answer

The solubility in mol/L is 12.7 g/L divided by 170 g/mol, which is 0.0747 mol/L. For MX2, the dissociation is MX2 ⇌ M^2+ + 2X^-. The concentration of M^2+ is 0.0747 mol/L and X^- is 2 × 0.0747 mol/L = 0.1494 mol/L. Ksp = [M^2+][X^-]^2 = (0.0747)(0.1494)^2 = 1.67 × 10^-3.

The Solubility of a Salt MX2 with a Molar Mass