25 ml of 0.10 M acetic acid is titrated with 0.10 M NaOH. What is the pH at the equivalence point? Ka for acetic acid = 1.8 × 10^-5.

Name: 25 ml of 0.10 M acetic acid is titrated with 0.10 M NaOH. What is the pH at the equivalence point? Ka for acetic acid = 1.8 × 10 -5 .
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The Answer of 25 ml of 0.10 M acetic acid is titrated with 0.10 M NaOH. What is the pH at the equivalence point? Ka for acetic acid = 1.8 × 10^-5.

25 Ml of 0