1.80 grams of an impure mixture containing sodium carbonate required 84.0 ml of 0.125 M H₂SO₄ for complete neutralization. What percent of the mixture is sodium carbonate?

Question

Quizplus · Accepted Answer

The reaction between sodium carbonate and sulfuric acid is: Na2CO3 + H2SO4 → Na2SO4 + CO2 + H2O. The moles of H2SO4 used are 0.125 M * 0.084 L = 0.0105 moles. Since the reaction ratio is 1:1, moles of Na2CO3 are also 0.0105. The molar mass of Na2CO3 is 106 g/mol, so the mass of Na2CO3 is 0.0105 moles * 106 g/mol = 1.113 g. The percentage of Na2CO3 in the mixture is (1.113 g / 1.80 g) * 100% = 61.83%, approximately 62%.

180 Grams of an Impure Mixture Containing Sodium Carbonate Required