0.653 g of a monoprotic acid (mm = 157 g/mol) is dissolved in water to produce 50.0 mL of a solution with pH = 2.13. Determine the ionization constant of the acid.

Question

Quizplus · Accepted Answer

The concentration of H⁺ ions is 10^(-2.13) M. The initial concentration of the acid is (0.653 g / 157 g/mol) / 0.050 L. Using the formula for the ionization constant, Ka = [H⁺][A⁻]/[HA], and assuming [H⁺] = [A⁻], we can solve for Ka, which is approximately 6.6 × 10⁻⁴.

0653 G of a Monoprotic Acid (Mm = 157 G/mol)