Consider the following equilibrium. A(g) + 3B(g) ⇌ 2C(g)
If the initial concentrations are [A(g)] = 1.00 M, [B(g)] = 3.00 M, and [C(g)] = 0, at equilibrium it is found that [C(g)] = 0.980 M. Calculate Kc for this reaction.

Question

Quizplus · Accepted Answer

The equilibrium constant (Kc) for a reaction is calculated using the concentrations of the reactants and products at equilibrium. For the given reaction, the equilibrium constant expression is:Kc = [C(g)]^2 / [A(g)] * [B(g)]^3Substituting the equilibrium concentrations into the expression, we get:Kc = (0.980 M)^2 / (1.00 M) * (3.00 M)^3 = 0.526Therefore, the equilibrium constant (Kc) for the given reaction is 0.526.

Consider the Following Equilibrium