For the reaction: 2N2O5(g) → 4NO2(g) + O2(g) the rate law is:
= k[N2O5] At 300 K, the half-life is 2.50 × 104 seconds and the activation energy is 103.3 kJ/mol O2. At the time when N2O5 is being consumed at a rate of -1.2 × 10-4 M/s, what is the rate at which NO2 is being formed?
A) 1.2 × 10-4 M/s
B) 2.4 × 10-4 M/s
C) 6.0 × 10-5 M/s
D) 3.0 × 10-5 M/s
E) 4.8 × 10-4 M/s
Correct Answer:
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