The solubility of CO in water at 0°C and 1 atm CO pressure is 0.0354 mg of CO in 1 mL of water. Calculate the molarity of aqueous CO solution at 2 atm CO pressure.

Question

Quizplus · Accepted Answer

Using Henry's law, we can calculate the new solubility of CO in water at 2 atm CO pressure:

S2 = S1 × P2/P1

where
S1 = 0.0354 mg/mL (given)
P1 = 1 atm (given)
P2 = 2 atm (given)
S2 = solubility at 2 atm (unknown)

Solving for S2:

S2 = 0.0354 mg/mL × 2 atm/1 atm
S2 = 0.0708 mg/mL

Now we can calculate the molarity of CO in water at 2 atm CO pressure:

Molarity = moles of solute / volume of solution

To find moles of solute, we need to convert the solubility from mg/mL to moles/L:

0.0708 mg/mL × (1 g/1000 mg) × (1 mol/28 g) × (1000 mL/1 L) = 2.52 × 10^-6 mol/L

Therefore, the molarity of CO in water at 2 atm CO pressure is:

Molarity = 2.52 × 10^-6 M = 2.53 × 10^-3 M = 2.53 × 10^-3 mol/L

The closest answer choice is D, 2.53 × 10^-3 M.

The Solubility of CO in Water at 0°C and 1