The vapor pressures of pure propyl alcohol and isopropyl alcohol are 21.0 mmHg and 45.2 mmHg,respectively,at 25 °C.Calculate the partial pressure of isopropyl alcohol above a solution in which the mole fraction of propyl alcohol is 0.250.

Question

Quizplus · Accepted Answer

The partial pressure of a component in a solution can be calculated using Raoult's Law, which states that the partial pressure of a component in a solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution. Given the mole fraction of propyl alcohol is 0.250, the mole fraction of isopropyl alcohol is 1 - 0.250 = 0.750. The partial pressure of isopropyl alcohol is then 45.2 mmHg * 0.750 = 33.9 mmHg.

The Vapor Pressures of Pure Propyl Alcohol and Isopropyl Alcohol