Given the bond enthalpies C=O (707), O=O (498), H-O (464), and C-H (414) in kJ/mol, compute ΔH° in kJ/mol for: CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g).

Name: Given the bond enthalpies C=O (707), O=O (498), H-O (464), and C-H (414) in kJ/mol, compute ΔH° in kJ/mol for: CH 4 (g) + 2 O 2 (g) → CO 2 (g) + 2 H 2 O(g).
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The Answer of Given the bond enthalpies C=O (707), O=O (498), H-O (464), and C-H (414) in kJ/mol, compute ΔH° in kJ/mol for: CH₄(g) + 2 O₂(g) → CO₂(g) + 2 H₂O(g).

Given the Bond Enthalpies C=O (707), O=O (498), H-O (464)