List in order of increasing size: K⁺, Se^{2^-}, Cl^-, Na⁺, S^{2^-}.

Question

Quizplus · Accepted Answer

The order of increasing size can be determined by looking at the atomic number and valence electron configuration of each ion. Na⁺ has the smallest size due to the small atomic number of Na compared to the other ions. K⁺ has a larger size than Na⁺ due to the larger atomic number of K. Cl^- is larger than Na⁺ due to the addition of an electron in the valence shell. S^{2^-} has a larger size than Cl^- due to the larger atomic number of S. Finally, Se^{2^-} has the largest size due to the larger atomic number of Se. Therefore, the correct order is Na⁺ < K⁺ < Cl^- < S^{2^-} < Se^{2^-}, which is given in option B.

List in Order of Increasing Size: K+, Se2-, Cl-, Na+

List in Order of Increasing Size: K⁺, Se^{2^-}, Cl^-, Na⁺