14.0 g of metal at 24.0°C has 250 joules of heat added to it. The metal's specific heat is 0.105 J/g °C. What is its final temperature?
A) (250) (14.0) /0.105 °C
B) [250/(14.0) (0.105) ] °C
C) [(914.0) (0.105) /250] + 24.0 °C
D) (14.0) (0.105) /250 °C
E) (14.0) (0.105) (250) °C
Correct Answer:
Verified
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