1219 joules of heat raise the temperature of 250 g of metal by 64°C. What is the specific heat in J/(g °C? )
A) (1219) (250) (64) J/(g°C)
B) (64) (250/1219) J/(g°C)
C) (1219) (64/250) J/(g°C)
D) (1219) (250/64) J/(g°C)
E) (1219) /(250 x 64) J/(g°C)
Correct Answer:
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