The standard enthalpy of formation of NH4Cl(s) is -315.4 kJ/mol. The equation that describes this △H°f is:
A) NH4+(aq) + Cl-(aq) → NH4Cl(s)
B) 1/2 N2(g) + 2H2(g) + 1/2 Cl2(g) → NH4Cl(s)
C) N2(g) + H2(g) + Cl2(g) → 2 NH4Cl(s)
D) 1/2 N2(g) + 1/2 Cl2(g) + 1/2 H2(g) → NH4Cl(s)
E) N2(g) + Cl2(g) + 4 H2(g) → 2 NH4Cl(s)
Correct Answer:
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