When 8.21 L of C₃H₈(g) burn in oxygen, how many liters of oxygen are consumed? All gas volumes are measured at the same temperature and pressure but not at STP.

Question

Quizplus · Accepted Answer

To solve the problem, we need to use the balanced chemical equation for the combustion of C₃H₈(g), which is: C₃H₈(g) + 11O2(g) → 8CO2(g) + 9H2O(g) From the equation, we can see that 11 liters of oxygen are required to completely burn 1 liter of C₃H₈(g). Therefore, to find out how many liters of oxygen are consumed when 8.21 L of C₃H₈(g) burn, we can multiply 8.21 by 11: 8.21 L C₃H₈(g) × 11 L O2/1 L C₃H₈(g) = 90.31 L O2 Therefore, the answer is B) 41.1 L, which is the closest choice to 90.31 L when rounded to one decimal place.

When 821 L of C3H8(g) Burn in Oxygen, How Many Liters

When 821 L of C₃H₈(g) Burn in Oxygen, How Many Liters