For the reaction 2 Al + Fe₂O₃ → Al₂O₃ + 2 Fe, 2.5 g of Al (27.0 g/mol) and 7.2 g of Fe₂O₃ (159.8 g/mol) produce how many g of Fe (55.9 g/mol)?

Question

Quizplus · Accepted Answer

The limiting reactant is Fe₂O₃. The moles of Fe produced are calculated using the stoichiometry of the reaction: (7.2 g Fe₂O₃ / 159.8 g/mol) * (2 mol Fe / 1 mol Fe₂O₃) * 55.9 g/mol Fe.

For the Reaction 2 Al + Fe2O3 → Al2O3

For the Reaction 2 Al + Fe₂O₃ → Al₂O₃