Iron metal reacts with chlorine gas as follows: 2 Fe(s) + 3 Cl2(g) → 2 FeCl3(s)
How many moles of FeCl3 are obtained when 4.6 mol of Cl2 reacts with excess Fe?
A) 3.1 mol
B) 4.6 mol
C) 1.5 mol
D) 2.3 mol
E) 6.9 mol
Correct Answer:
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