What volume of concentrated acetic acid (CH₃CO₂H, density 1.05 g mL-1) is needed to prepare 250 mL of a 0.30 M aqueous solution?

Question

Quizplus · Accepted Answer

First, we need to calculate the number of moles of acetic acid needed to prepare 250 mL of a 0.30 M solution.

moles = Molarity x volume (in L) = 0.30 mol/L x 0.250 L = 0.075 mol

Next, we can use the density and molar mass of acetic acid to calculate the volume of concentrated acetic acid needed.

mass = volume x density

volume = mass / density

mass = moles x molar mass

mass = 0.075 mol x 60.05 g/mol = 4.508 g

volume = 4.508 g / 1.05 g/mL = 4.3 mL

Therefore, the best choice is B) 4.3 mL, as this is the calculated volume of concentrated acetic acid needed to prepare 250 mL of a 0.30 M solution.

What Volume of Concentrated Acetic Acid (CH3CO2H, Density 1