How many grams of H₂O are there in 10.0 g of tetraphenylarsonium chloride dihydrate, (C₆H₅)₄AsCl · 2 H₂O?

Question

Quizplus · Accepted Answer

To determine the amount of H₂O in the given compound, we need to calculate the molecular weight of (C₆H₅)₄AsCl · 2 H₂O. Molecular weight of (C₆H₅)₄AsCl: - C: 16 x 12.01 = 192.16 - H: 15 x 1.01 = 15.15 - S: 1 x 32.06 = 32.06 - As: 1 x 74.92 = 74.92 - Cl: 1 x 35.45 = 35.45 Total molecular weight = 349.54 g/mol Molecular weight of 2 H₂O: - 2 x H: 2 x 1.01 = 2.02 - 2 x S: 2 x 32.06 = 64.12 - 2 x O: 2 x 16.00 = 32.00 Total molecular weight = 98.14 g/mol Total molecular weight of the compound: 349.54 + 98.14 = 447.68 g/mol Now, we can use the following calculation to determine the amount of H₂O in 10.0 g of the compound: (10.0 g compound) x (1 mol/447.68 g) x (2 mol H₂O/1 mol compound) x (78.10 g/mol H₂O) = 0.792 g H₂O Therefore, the answer is B.

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