If 6.00 grams of a 8.00 gram sample of a radioactive substance undergoes decay in 180 minutes, then the half-life of the substance is

Question

Quizplus · Accepted Answer

To find the half-life of the substance, we can use the formula:

N = N₀(1/2)^(t/h)

where:
N₀ = initial amount of substance
N = amount of substance remaining after time t
h = half-life of substance

In this case, we know that:

N₀ = 8.00 g
N = 8.00 g - 6.00 g = 2.00 g (since 6.00 g of the substance has undergone decay)
t = 180 minutes

Plugging in these values, we get:

2.00 g = 8.00 g (1/2)^(180/h)

Simplifying, we get:

(1/2)^(180/h) = 0.25

Taking the logarithm of both sides (with base 1/2), we get:

180/h = log(0.25)/log(1/2)

180/h = 2

h = 90 minutes

Therefore, the half-life of the substance is 90 minutes, which is option B.

If 600 Grams of a 8