Recombination frequencies can be calculated by:
A) counting the number of recombinant and parental offspring when an individual who is heterozygous for two genes is testcrossed.
B) performing a chi-square test on the F2 progeny when an individual who is homozygous for two genes is initially crossed to an individual who is homozygous recessive for these two genes.
C) counting the number of offspring who are expressing the dominant phenotype when a heterozygous individual for two genes is testcrossed.
D) performing a chi-square test of the progeny of a cross between parents who are both heterozygous for the same two genes.
E) counting the number of offspring that are found in the cross of an individual who is heterozygous for two genes with another parent who is homozygous dominant for one of these genes and homozygous recessive for the other gene.
Correct Answer:
Verified
Q1: Linked genes:
A)assort randomly.
B)can't crossover and recombine.
C)are allelic.
D)segregate
Q2: Two linked genes, (A)and (B), are separated
Q6: Genetic distances within a given linkage group:
A)cannot
Q7: A linkage group:
A)involves on or more genes
Q8: You are doing lab work with a
Q9: Dr.Disney has been raising exotic fruit flies
Q10: Linked genes always exhibit:
A)phenotypes that are similar.
B)recombination
Q20: Recombination occurs through:
A) crossing over and chromosome
Q20: Recombination occurs through:
A) crossing over and chromosome
Q43: Linked genes are:
A) allelic.
B) dominant.
C) on different
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