Dr.Disney has been raising exotic fruit flies for decades.Recently, he discovered a strain of fruit flies that in the recessive condition have baby blue eyes that he designates as bb.He also has another strain of fruit flies that in the recessive condition have pink wings that are designated as pw.He is able to establish flies that are homozygous for both mutant traits.He mates these two strains with each other.Dr.Disney then takes phenotypically wild-type females from this cross and mates them with double recessive males.In the resulting testcross progeny, he observes 500 flies that are of the following make-up:
Assuming the wild-type alleles for these two genes are b+ and pw+, what is the CORRECT testcross of the F1 flies?
A) bb+ pw+/bb pw × bb pw/bb pw
B) bb+ pw+/bb pw × bb pw+/bb+ pw
C) bb+ pw/bb pw+ × bb pw/bb pw
D) bb+ pw/bb pw+ × bb+ pw+/bb pw
E) bb+ pw+/bb pw × bb+ pw/bb pw+
Correct Answer:
Verified
Q4: Recombination frequencies can be calculated by:
A)counting the
Q6: Genetic distances within a given linkage group:
A)cannot
Q7: A linkage group:
A)involves on or more genes
Q8: You are doing lab work with a
Q10: Linked genes always exhibit:
A)phenotypes that are similar.
B)recombination
Q12: A genetic map shows which of the
Q14: You are doing lab work with a
Q19: A testcross includes:
A) one parent who is
Q20: Recombination occurs through:
A) crossing over and chromosome
Q20: Recombination occurs through:
A) crossing over and chromosome
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