Two linked genes, (A)and (B), are separated by 18 cM.A man with genotype Aa Bb marries a woman who is aa bb.The man's father was AA BB.What is the probability that their first two children will both be ab/ab?
A)0)168
B)0)0081
C)0)032
D)0)062
E)0)13

Question

Quizplus · Accepted Answer

The correct answer is A.The probability of the first child being ab/ab is 0.084. The probability of the second child being ab/ab is also 0.084. The probability of both children being ab/ab is 0.084 * 0.084 = 0.007056.

Two Linked Genes, (A)and (B), Are Separated by 18 CM