How many grams of glucose (C₆H₁₂O₆)are contained in 555 mL of a 1.77 M glucose solution?

Question

Quizplus · Accepted Answer

To find the grams of glucose in the solution, use the formula: mass = molarity (M) × volume (L) × molar mass of solute. First, convert 555 mL to liters (0.555 L). The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol. Therefore, the mass of glucose is 1.77 M × 0.555 L × 180.16 g/mol = 176.9 g, which rounds to 177 g.

How Many Grams of Glucose (C6H12O6)are Contained in 555 ML

How Many Grams of Glucose (C₆H₁₂O₆)are Contained in 555 ML