What is the concentration of a solution formed by diluting 25.0 mL of a 3.2 M NaCl solution to 135.0 mL?

Question

Quizplus · Accepted Answer

The concentration after dilution can be calculated using the formula $C_1V_1 = C_2V_2$, where $C_1$ and $C_2$ are the initial and final concentrations, and $V_1$ and $V_2$ are the initial and final volumes, respectively. Substituting the given values: $3.2 \, \text{M} \times 25.0 \, \text{mL} = C_2 \times 135.0 \, \text{mL}$. Solving for $C_2$ gives $C_2 = \frac{3.2 \, \text{M} \times 25.0 \, \text{mL}}{135.0 \, \text{mL}} = 0.59 \, \text{M}$.

What Is the Concentration of a Solution Formed by Diluting