What is the concentration of a solution formed by adding 65.0 mL of water to 25.0 mL of a 3.2 M NaCl solution?

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Quizplus · Accepted Answer

The concentration of the new solution can be calculated using the formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the concentration and volume of the initial solution, and $C_2$ and $V_2$ are the concentration and volume of the final solution. Here, $C_1 = 3.2$ M, $V_1 = 25.0$ mL, and $V_2 = 25.0 + 65.0 = 90.0$ mL. Solving for $C_2$, we get $C_2 = \frac{3.2 \times 25.0}{90.0} = 0.89$ M NaCl.

What Is the Concentration of a Solution Formed by Adding