A gas cylinder containing 6.38 mol of neon has a pressure of 491 mm Hg at 295 K. If 3.22 mol of helium is added to this cylinder,at constant temperature and volume,what will be the pressure in the cylinder?

Question

Quizplus · Accepted Answer

The total moles of gas after adding helium will be 6.38 mol (neon) + 3.22 mol (helium) = 9.6 mol. According to the ideal gas law (PV=nRT), at constant temperature and volume, the pressure of a gas is directly proportional to the number of moles. Therefore, the final pressure can be calculated by multiplying the initial pressure by the ratio of final moles to initial moles: $491 \, \text{mm Hg} \times \frac{9.6 \, \text{mol}}{6.38 \, \text{mol}} = 739 \, \text{mm Hg}$.

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