Consider the reaction: PCl₃(g)+ Cl₂(g) PCl₅(g). If [PCl₃] = 0.78 M, [Cl₂] = 0.44 M, and [PCl₅] = 0.88 at equilibrium, what is the value of K?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is:

PCl3(g) + Cl2(g) ↔ PCl5(g)

At equilibrium, we have the following equilibrium concentrations:

[PCl3] = 0.78 M
[Cl2] = 0.44 M
[PCl5] = 0.88 M

We can now use these concentrations to calculate the equilibrium constant Kc:

Kc = [PCl5]/([PCl3][Cl2]) = (0.88)/(0.78*0.44) = 2.6

Therefore, the answer is choice C.

Consider the Reaction: PCl3(g)+ Cl2(g) PCl5(g)