Consider the reaction: N₂(g)+ O₂(g) 2 NO(g). If [N₂] = 0.520 M, [O₂] = 0.0662 M, and [NO] = 0.00956 at equilibrium, what is the value of K?

Question

Quizplus · Accepted Answer

The balanced chemical equation for the reaction is: N₂(g) + O₂(g) → 2 NO(g) The equilibrium constant expression is: K = [NO]2/([N₂][O₂]) Substituting the given equilibrium concentrations gives: K = (0.00956)2/[(0.520)(0.0662)] = 0.00265 (rounded to four significant figures)

Consider the Reaction: N2(g)+ O2(g) 2 NO(g)

Consider the Reaction: N₂(g)+ O₂(g) 2 NO(g)