Consider the combustion reaction of propane: C₃H₈(g)+ 5 O₂(g)$\rightarrow$ 3 CO₂(g)+ 4 H₂O(g), where $\Delta$H = -531 kcal. If 1.24 × 10⁵ kcal of energy is released in the reaction, how many moles of propane were burned?

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The Answer of Consider the combustion reaction of propane: C₃H₈(g)+ 5 O₂(g)$\rightarrow$ 3 CO₂(g)+ 4 H₂O(g), where $\Delta$H = -531 kcal. If 1.24 × 10⁵ kcal of energy is released in the reaction, how many moles of propane were burned?

Consider the Combustion Reaction of Propane: C3H8(g)+ 5 O2(g) →\rightarrow→ 3 CO2(g)+ 4 H2O(g), Where

Consider the Combustion Reaction of Propane: C₃H₈(g)+ 5 O₂(g) $\rightarrow$ 3 CO₂(g)+ 4 H₂O(g), Where