CH₄ + 4Cl₂(g) $\rightarrow$ CCl₄(g) + 4HCl(g) $\Delta$ H = -434 KJ Based on the Above Reaction, What

CH₄ + 4Cl₂(g) $\rightarrow$ CCl₄(g) + 4HCl(g) , $\Delta$ H = -434 kJ Based on the above reaction, what energy change occurs when 1.8 mol of methane reacts?

A) 2.4 *10⁵ J is released.
B) 7.8 * 10⁵ J is released.
C) 2.4 *10⁵ J is absorbed.
D) 7.8 *10⁵ J is absorbed.
E) 4.3*10² J is released.