Consider a process carried out on 1.00 mol of a monatomic ideal gas by the following two different pathways. The first pathway is A (3.00 atm, 20.0 L) to C (1.00 atm, 20.0 L) to D (1.00 atm, 50.0 L) ; and the second pathway is A (3.00 atm, 20.0 L) to B (3.00 atm, 50.0 L) to D (1.00 atm, 50.0 L) . In each case, the gas is taken from state A to state D.
-Calculate w_AB.

Question

Quizplus · Accepted Answer

To calculate w_AB, we need to use the equation: w = -PΔV where P is the pressure and ΔV is the change in volume. For pathway 1: ΔV = (50.0 L - 20.0 L) = 30.0 L (since the volume stays constant at 20.0 L between A and C) w1 = -3.00 atm * 30.0 L = -90.0 L•atm For pathway 2: ΔV = (50.0 L - 20.0 L) + (50.0 L - 50.0 L) = 30.0 L w2 = -3.00 atm * 30.0 L = -90.0 L•atm Since w_AB = w1 - w2, we get: w_AB = (-90.0 L•atm) - (-90.0 L•atm) = -90.0 L•atm Therefore, the answer is C, -90 L•atm.

Consider a Process Carried Out on 1