When 0.157 mol of NH₃ is reacted with excess HCl, 6.91 kJ of energy is released as heat. What is $\Delta$H for this reaction per mole of NH₃ consumed?

Name: When 0.157 mol of NH 3 is reacted with excess HCl, 6.91 kJ of energy is released as heat. What is $\Delta$H for this reaction per mole of NH 3 consumed?
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Question

Quizplus · Accepted Answer

The energy released per mole of NH₃ is calculated by dividing the total energy released by the number of moles of NH₃. Thus, ΔH = -6.91 kJ / 0.157 mol = -44.0 kJ/mol.

When 0157 Mol of NH3 Is Reacted with Excess HCl, 6

When 0157 Mol of NH₃ Is Reacted with Excess HCl, 6