One mole of a liquid is vaporized at its boiling point, 65°C and 1.00 atm. Hvap for the liquid is 43.8 kJ/mol at 65° C.
-Calculate w.
A) -27.7 J
B) 27.7 J
C) 2.81 * 103 J
D) -2.81 * 103 J
E) none of these
Correct Answer:
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