A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 *10^-3 M CuNO₃. Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium:
-[Cu⁺]

Question

A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 *10^-3 M CuNO₃. Cu(I) forms complex ions with cyanide as follows:

A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 *10<sup>-3</sup> M CuNO<sub>3</sub>. Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu<sup>+</sup>] A) 2.0 * 10<sup>-13</sup> M B) 8.0 *10<sup>-15</sup> M C) 1.6 * 10<sup>-13</sup> M D) 4.0 * 10<sup>-13</sup> M E) none of these

Calculate the following concentrations at equilibrium:
-[Cu⁺]

Quizplus · Accepted Answer

The Answer of A solution is formed by mixing 50.0 mL of 10.00 M NaCN with 50.0 mL of 2.0 *10 -3 M CuNO 3 . Cu(I) forms complex ions with cyanide as follows: Calculate the following concentrations at equilibrium: -[Cu⁺]

A Solution Is Formed by Mixing 50