What volume of carbon dioxide measured at STP will be formed by the reaction of 1.30 mol of oxygen with 9.00 * 10^-¹ mol of ethyl alcohol (CH₃CH₂OH)?

Question

Quizplus · Accepted Answer

The balanced equation for the combustion of ethyl alcohol is: C2H5OH + 3O2 → 2CO2 + 3H2O. From the stoichiometry, 1 mol of C2H5OH produces 2 mol of CO2. Therefore, 9.00 x 10^-1 mol of C2H5OH will produce 1.80 mol of CO2. At STP, 1 mol of gas occupies 22.4 L, so 1.80 mol of CO2 will occupy 1.80 x 22.4 L = 40.32 L. However, the limiting reactant is oxygen, which is 1.30 mol, producing 1.30 x (2/3) = 0.867 mol of CO2, which occupies 0.867 x 22.4 L = 19.4 L.

What Volume of Carbon Dioxide Measured at STP Will Be