What volume of 6.60 M potassium hydroxide is required to prepare 53.6 mL of 0.450 M KOH?

Question

Quizplus · Accepted Answer

We can use the formula:

M1V1 = M2V2

where M1 is the concentration of the original solution, V1 is the volume of the original solution, M2 is the concentration of the final solution, and V2 is the volume of the final solution.

Plugging in the values we have:

(6.60 M)V1 = (0.450 M)(53.6 mL)

V1 = (0.450 M)(53.6 mL)/(6.60 M) = 3.65 mL

Therefore, the volume of the 6.60 M potassium hydroxide required is 3.65 mL, which corresponds to choice C.

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