When the equation C₄H₁₀ + O₂ $\rightarrow$ CO₂ + H₂O is balanced with the smallest set of integers, the sum of the coefficients is

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To balance the equation, we need to make sure that the number of atoms of each element is equal on both sides. Starting with carbon, we see that there is 1 carbon on the left side and 1 carbon on the right side. Then moving to sulfur, there are 2 sulfurs on the left side and 2 sulfurs on the right side. For oxygen, there are 12 oxygens on the left side and 12 oxygens on the right side. Finally, looking at hydrogen, there are 14 hydrogens on the left side and 14 hydrogens on the right side. The coefficients for each compound are: C₄H₁₀: 1 + 1 + 11 = 13 O₂: 12 F1F1F1S1F1F1F10 CO₂: 1 H₂O: 1 + 12 = 13 In total, the sum of the coefficients is: 13 + 12 + 1 + 13 = 39. However, we need to find the smallest set of integers, so we can divide all coefficients by 3 to get: 4 + 4 + 1 + 4 = 13. Therefore, the answer is (C) 33.

When the Equation C4H10 + O2 →\rightarrow→ CO2 + H2O Is Balanced with the Smallest Set of Is

When the Equation C₄H₁₀ + O₂ $\rightarrow$ CO₂ + H₂O Is Balanced with the Smallest Set of Is